Cab Flatbed
Could anyone offer some assistance?
A flatbed truck is carrying a heavy crate. The coefficient of static friction between the crate and the bed of the truck is 0.71. What is the maximum rate at which the driver can decelerate and still avoid having the crate slide against the cab?
The frictional force preventing the crate from slipping is
f = - mu(mg)
where
mu = coeff of friction = 0.71 given
m = mass of the crate
g = acceleration due to gravity = 9.8 m/sec^2 (constant)
and the negative sign simply indicates that the frictional force is opposite that of the motion of the truck.
Using Newton's Second Law of Motion,
- (mu)(mg) = ma
Since "m" appears on both sides of the equation, it will simply cancel out, hence the above becomes
a = - (mu)(g) = - 0.71* 9.8
a = -6.96 m/sec^2
Hope this helps.
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